What is area 8cos(4x),8-8cos(4x),0, pi/4 ?

The answer to area 8cos(4x),8-8cos(4x),0, pi/4 is -(4pi)/3+2pi+4sqrt(3)

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area 8cos(4x),8-8cos(4x),0, pi/4

area

8 cos (4 x), 8 - 8 cos (4 x), 0, \frac{π}{4}

- \frac{4 π}{3} + 2 π + 43

Decimal

9.02259 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{4}} ∣ 8 cos (4 x) - (8 - 8 cos (4 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{4}} ∣ 8 cos (4 x) - (8 - 8 cos (4 x)) ∣ d x : - \frac{4 π}{3} + 2 π + 43

The area is:

= - \frac{4 π}{3} + 2 π + 43

\frac{d}{d x} (\frac{2 x}{2 + x})

\frac{d}{d x} (cos (\frac{1 - e ^{4 x}}{1 + e ^{4 x}}))

\int x cos (3 π x^{2}) d x

ln (x) y^{^{'}} = \frac{y}{x}

f (x) = - x, at x = - 4

What is area 8cos(4x),8-8cos(4x),0, pi/4 ?
The answer to area 8cos(4x),8-8cos(4x),0, pi/4 is -(4pi)/3+2pi+4sqrt(3)