What is the derivative of y=\sqrt[4]{x} ?

The derivative of y=\sqrt[4]{x} is 1/(4x^{3/4)}

What is the first derivative of y=\sqrt[4]{x} ?

The first derivative of y=\sqrt[4]{x} is 1/(4x^{3/4)}

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derivative of

y = 4 x

\frac{1}{4 x ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (4 x)

Apply radical rule:

n a = a^{\frac{1}{n}}

= \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

\frac{1}{4} x^{\frac{1}{4} - 1} : \frac{1}{4 x ^{\frac{3}{4}}}

= \frac{1}{4 x ^{\frac{3}{4}}}

y = \frac{x}{8 + x}

\frac{d}{d x} (cot^{7} (x))

2 y y^{^{'}} + 2 = y^{2} + 2 x, y (0) = 4

\frac{2 x}{( x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (x^{3} + 2 x^{2} - x + 4)

What is the derivative of y=\sqrt[4]{x} ?
The derivative of y=\sqrt[4]{x} is 1/(4x^{3/4)}
What is the first derivative of y=\sqrt[4]{x} ?
The first derivative of y=\sqrt[4]{x} is 1/(4x^{3/4)}