What is the derivative of (2x)/((x^2+1)^2) ?

The derivative of (2x)/((x^2+1)^2) is (2(-3x^2+1))/((x^2+1)^3)

What is the first derivative of (2x)/((x^2+1)^2) ?

The first derivative of (2x)/((x^2+1)^2) is (2(-3x^2+1))/((x^2+1)^3)

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derivative of

\frac{2 x}{( x ^{2} + 1 ) ^{2}}

\frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 x}{( x ^{2} + 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 1 ) ^{2} - \frac{d}{d x} ( ( x ^{2} + 1 ) ^{2} ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} + 1)^{2}) = 4 x (x^{2} + 1)

= 2 \cdot \frac{1 \cdot ( x ^{2} + 1 ) ^{2} - 4 x ( x ^{2} + 1 ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x ^{2} + 1 ) ^{2} - 4 x ( x ^{2} + 1 ) x}{( ( x ^{2} + 1 ) ^{2} ) ^{2}} : \frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}}

= \frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}}

\frac{d}{d x} (x^{3} + 2 x^{2} - x + 4)

\int \frac{1}{x ^{2} - x ^{3}} d x

\frac{\partial}{\partial x} (ln (2 x - y))

\int_{0}^{9} 9 + 3 x d x

3 t^{2}

What is the derivative of (2x)/((x^2+1)^2) ?
The derivative of (2x)/((x^2+1)^2) is (2(-3x^2+1))/((x^2+1)^3)
What is the first derivative of (2x)/((x^2+1)^2) ?
The first derivative of (2x)/((x^2+1)^2) is (2(-3x^2+1))/((x^2+1)^3)