What is the limit as x approaches-1-of (x+1)/(x^4-1) ?

The limit as x approaches-1-of (x+1)/(x^4-1) is -1/4

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limit as x approaches-1-of (x+1)/(x^4-1)

x \to - 1 - lim (\frac{x + 1}{x ^{4} - 1})

- \frac{1}{4}

Decimal

- 0.25

Solution steps

x \to - 1 - lim (\frac{x + 1}{x ^{4} - 1})

Simplify

\frac{x + 1}{x ^{4} - 1} : \frac{1}{( x ^{2} + 1 ) ( x - 1 )}

= x \to - 1 - lim (\frac{1}{( x ^{2} + 1 ) ( x - 1 )})

Plug in the value

x = - 1

= \frac{1}{( ( - 1 ) ^{2} + 1 ) ( - 1 - 1 )}

Simplify

\frac{1}{( ( - 1 ) ^{2} + 1 ) ( - 1 - 1 )} : - \frac{1}{4}

= - \frac{1}{4}

n = 0 \sum \infty \frac{1}{2 ^{n - 1}}

\frac{x ^{4}}{2} - \frac{2}{x ^{4}} + 6 x

\frac{d}{d x} (arcsin (5 x - 1))

\int_{- 2}^{0} \frac{5}{x ^{2} + 4 x + 8} d x

x \to 4 lim (- x^{2} + 3 x - 7)

What is the limit as x approaches-1-of (x+1)/(x^4-1) ?
The limit as x approaches-1-of (x+1)/(x^4-1) is -1/4