What is the limit as x approaches 0 of ((3+x)^2-9)/x ?

The limit as x approaches 0 of ((3+x)^2-9)/x is 6

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limit as x approaches 0 of ((3+x)^2-9)/x

x \to 0 lim (\frac{( 3 + x ) ^{2} - 9}{x})

6

Solution steps

x \to 0 lim (\frac{( 3 + x ) ^{2} - 9}{x})

Simplify

\frac{( 3 + x ) ^{2} - 9}{x} : x + 6

= x \to 0 lim (x + 6)

Plug in the value

x = 0

= 0 + 6

Simplify

= 6

4 x^{2} y^{^{''}} + 17 y = 0

f (, at)

y^{^{'}} + x y = - 5 x y^{4}

\int (x^{3} + 2 x) sin (x) d x

x \to 3 lim (7 + 6 (- 7))

What is the limit as x approaches 0 of ((3+x)^2-9)/x ?
The limit as x approaches 0 of ((3+x)^2-9)/x is 6