What is the integral of (x^2)/(sqrt(a^2+x^2)) ?

The integral of (x^2)/(sqrt(a^2+x^2)) is 1/2 xsqrt(x^2+a^2)-(a^2)/2 ln((|x+sqrt(x^2+a^2)|)/(|a|))+C

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integral of (x^2)/(sqrt(a^2+x^2))

\int \frac{x ^{2}}{a ^{2} + x ^{2}} d x

\frac{1}{2} x x^{2} + a^{2} - \frac{a ^{2}}{2} ln (\frac{x + x ^{2} + a ^{2}}{∣ a ∣}) + C

Solution steps

\int \frac{x ^{2}}{a ^{2} + x ^{2}} d x

Apply Trigonometric Substitution

: \int a^{2} tan^{2} (u) sec (u) d u

= \int a^{2} tan^{2} (u) sec (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a^{2} \cdot \int tan^{2} (u) sec (u) d u

Rewrite using trig identities

= a^{2} \cdot \int (- 1 + sec^{2} (u)) sec (u) d u

Expand

(- 1 + sec^{2} (u)) sec (u) : - sec (u) + sec^{3} (u)

= a^{2} \cdot \int - sec (u) + sec^{3} (u) d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= a^{2} (- \int sec (u) d u + \int sec^{3} (u) d u)

\int sec (u) d u = ln ∣ tan (u) + sec (u) ∣

\int sec^{3} (u) d u = \frac{1}{2} sec (u) tan (u) + \frac{1}{2} ln ∣ tan (u) + sec (u) ∣

= a^{2} (- ln ∣ tan (u) + sec (u) ∣ + \frac{1}{2} sec (u) tan (u) + \frac{1}{2} ln ∣ tan (u) + sec (u) ∣)

Substitute back

u = arctan (\frac{1}{a} x)

= a^{2} (- ln tan (arctan (\frac{1}{a} x)) + sec (arctan (\frac{1}{a} x)) + \frac{1}{2} sec (arctan (\frac{1}{a} x)) tan (arctan (\frac{1}{a} x)) + \frac{1}{2} ln tan (arctan (\frac{1}{a} x)) + sec (arctan (\frac{1}{a} x)))

Simplify

a^{2} (- ln tan (arctan (\frac{1}{a} x)) + sec (arctan (\frac{1}{a} x)) + \frac{1}{2} sec (arctan (\frac{1}{a} x)) tan (arctan (\frac{1}{a} x)) + \frac{1}{2} ln tan (arctan (\frac{1}{a} x)) + sec (arctan (\frac{1}{a} x))) : \frac{1}{2} x x^{2} + a^{2} - \frac{a ^{2}}{2} ln (\frac{x + x ^{2} + a ^{2}}{∣ a ∣})

= \frac{1}{2} x x^{2} + a^{2} - \frac{a ^{2}}{2} ln (\frac{x + x ^{2} + a ^{2}}{∣ a ∣})

Add a constant to the solution

= \frac{1}{2} x x^{2} + a^{2} - \frac{a ^{2}}{2} ln (\frac{x + x ^{2} + a ^{2}}{∣ a ∣}) + C

\int (sin (x^{3})) d x

y^{^{'}} (x) = \frac{( 1 + 3 x ^{2} )}{3 y ^{2} - 6 y}, y (0) = 1

\frac{d}{d x} (a x cos (2 x) + b x sin (2 x))

\frac{\partial}{\partial x} (cos (x) \cdot sin (x))

\frac{d}{d x} (1 + e^{x^{2}})

What is the integral of (x^2)/(sqrt(a^2+x^2)) ?
The integral of (x^2)/(sqrt(a^2+x^2)) is 1/2 xsqrt(x^2+a^2)-(a^2)/2 ln((|x+sqrt(x^2+a^2)|)/(|a|))+C