What is the derivative of 1+e^{x^2} ?

The derivative of 1+e^{x^2} is 2e^{x^2}x

What is the first derivative of 1+e^{x^2} ?

The first derivative of 1+e^{x^2} is 2e^{x^2}x

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\frac{d}{d x} (1 + e^{x^{2}})

2 e^{x^{2}} x

Solution steps

\frac{d}{d x} (1 + e^{x^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (e^{x^{2}})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

= 0 + e^{x^{2}} \cdot 2 x

Simplify

= 2 e^{x^{2}} x

\frac{d}{d x} (ln ∣ ln (x) ∣)

y = x^{(\frac{1}{l n ( x )})}

\int sin^{5} (x) \cdot cos^{5} (x) d x

x \to 0 lim (\frac{7}{cos ( x )})

\frac{d x}{d y} + \frac{1}{y ^{2}} x = \frac{1}{y ^{2}}

What is the derivative of 1+e^{x^2} ?
The derivative of 1+e^{x^2} is 2e^{x^2}x
What is the first derivative of 1+e^{x^2} ?
The first derivative of 1+e^{x^2} is 2e^{x^2}x