What is the integral of 1/(sqrt(x+5)) ?

The integral of 1/(sqrt(x+5)) is 2sqrt(x+5)+C

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integral of 1/(sqrt(x+5))

\int \frac{1}{x + 5} d x

2 x + 5 + C

Solution steps

\int \frac{1}{x + 5} d x

Apply u-substitution

: \int 2 d u

= \int 2 d u

Integral of a constant:

\int a d x = a x

= 2 u

Substitute back

u = x + 5

= 2 x + 5

Add a constant to the solution

= 2 x + 5 + C

e^{- 3 t} + 3

\int \frac{- t}{( t + 1 ) - ( t + 1 )} d t

\frac{\partial}{\partial t} (\frac{3 y ^{2} - t ^{2}}{y ^{5}})

x \to 0 lim (\frac{( 3 ^{x} - 1 )}{x})

\int_{0}^{6} π (36 x^{2} - x^{4}) d x

What is the integral of 1/(sqrt(x+5)) ?
The integral of 1/(sqrt(x+5)) is 2sqrt(x+5)+C