What is (\partial)/(\partial x)(x^2+2y^2+3z^2-9) ?

The answer to (\partial)/(\partial x)(x^2+2y^2+3z^2-9) is 2x

Popular >

(\partial)/(\partial x)(x^2+2y^2+3z^2-9)

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} + 3 z^{2} - 9)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} + 3 z^{2} - 9)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (2 y^{2}) + \frac{\partial}{\partial x} (3 z^{2}) - \frac{\partial}{\partial x} (9)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

\frac{\partial}{\partial x} (3 z^{2}) = 0

\frac{\partial}{\partial x} (9) = 0

= 2 x + 0 + 0 - 0

Simplify

= 2 x

\int_{2}^{6} ln (x) d x

x \to - 3 lim (\frac{x ^{2} - 9}{x + 3})

f (x) = sin (sin (x)), at x = (4 π)

\int cos (2 x) + 1 d x

What is (\partial)/(\partial x)(x^2+2y^2+3z^2-9) ?
The answer to (\partial)/(\partial x)(x^2+2y^2+3z^2-9) is 2x