What is the integral of-18x^{-19} ?

The integral of-18x^{-19} is 1/(x^{18)}+C

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integral of-18x^{-19}

\int - 18 x^{- 19} d x

\frac{1}{x ^{18}} + C

Solution steps

\int - 18 x^{- 19} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 18 \cdot \int x^{- 19} d x

Apply the Power Rule

: - \frac{1}{18 x ^{18}}

= - 18 (- \frac{1}{18 x ^{18}})

Simplify

- 18 (- \frac{1}{18 x ^{18}}) : \frac{1}{x ^{18}}

= \frac{1}{x ^{18}}

Add a constant to the solution

= \frac{1}{x ^{18}} + C

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