What is the integral of 2/(\sqrt[4]{x^3)} ?

The integral of 2/(\sqrt[4]{x^3)} is 8\sqrt[4]{x}+C

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integral of 2/(\sqrt[4]{x^3)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 2 \cdot \int \frac{1}{x ^{\frac{3}{4}}} d x

Apply the Power Rule

: 4 x^{\frac{1}{4}}

= 2 \cdot 4 x^{\frac{1}{4}}

Simplify

Add a constant to the solution

f (x) = \frac{3 x}{x + 1}, (2, 2)

\int_{0}^{3} x 1 + 2 x d x

\int (y^{2} + ln (x)) d y

\int_{0}^{5} 7 x - x^{2} - 2 x d x

x \to 0 lim (sec (x))

What is the integral of 2/(\sqrt[4]{x^3)} ?
The integral of 2/(\sqrt[4]{x^3)} is 8\sqrt[4]{x}+C