What is the derivative of y=x^2+1 ?

The derivative of y=x^2+1 is 2x

What is the first derivative of y=x^2+1 ?

The first derivative of y=x^2+1 is 2x

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derivative of

y = x^{2} + 1

2 x

Solution steps

\frac{d}{d x} (x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Simplify

= 2 x

\frac{d}{d x} (\frac{x ^{4}}{4 - x ^{3}})

cos (x) - 4 tan (x)

\frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2})

(2 x^{3} + 4) (x^{4} - 4 x)

\frac{6}{x ^{3}} - \frac{6}{x ^{2}} - \frac{1}{x} + 350