What is (\partial)/(\partial x)(8-x^2-3y^2) ?

The answer to (\partial)/(\partial x)(8-x^2-3y^2) is -2x

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(\partial)/(\partial x)(8-x^2-3y^2)

\frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (8 - x^{2} - 3 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8) - \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (8) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 0 - 2 x - 0

Simplify

= - 2 x

(2 x^{3} + 4) (x^{4} - 4 x)

\frac{6}{x ^{3}} - \frac{6}{x ^{2}} - \frac{1}{x} + 350

\frac{d}{d x} (x^{3} + 5 x)

\frac{d}{d x} (2 x + 2 x ln (x))

(4 x + 4)^{\frac{1}{3}}, at x = 2

What is (\partial)/(\partial x)(8-x^2-3y^2) ?
The answer to (\partial)/(\partial x)(8-x^2-3y^2) is -2x