What is derivative of f(x)=e^{4tsin(2t)} ?

The answer to derivative of f(x)=e^{4tsin(2t)} is (dt)/(dx)=0

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derivative of f(x)=e^{4tsin(2t)}

derivative of

f (x) = e^{4 t s i n (2 t)}

\frac{d t}{d x} = 0

Solution steps

f (x) = e^{4 t s i n (2 t)}

Treat

t

t (x)

Differentiate both sides:

0 = e^{4 t s i n (2 t)} \cdot 4 (\frac{d t}{d x} sin (2 t) + cos (2 t) \cdot 2 \frac{d t}{d x} t)

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

y^{^{'}} = e^{(t + y)}, y (0) = 0

x^{2} (\frac{d y}{d x}) + 4 x y - y^{3} = 0

x \to 2 lim ((3 x - 1)^{x^{2} - 3 x + 4})

\frac{\partial}{\partial y} (ln (\frac{x}{y}))

\frac{\partial}{\partial y} (x e^{y} + y e^{z} + z e^{x})

What is derivative of f(x)=e^{4tsin(2t)} ?
The answer to derivative of f(x)=e^{4tsin(2t)} is (dt)/(dx)=0