What is the integral of x/(4+2x^2) ?

The integral of x/(4+2x^2) is 1/4 ln|4+2x^2|+C

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integral of x/(4+2x^2)

\int \frac{x}{4 + 2 x ^{2}} d x

\frac{1}{4} ln 4 + 2 x^{2} + C

Solution steps

\int \frac{x}{4 + 2 x ^{2}} d x

Apply u-substitution

: \int \frac{1}{4 u} d u

= \int \frac{1}{4 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{4} ln ∣ u ∣

Substitute back

u = 4 + 2 x^{2}

= \frac{1}{4} ln 4 + 2 x^{2}

Add a constant to the solution

= \frac{1}{4} ln 4 + 2 x^{2} + C

\frac{d}{d x} (c f (x) + f (x) (c x))

\frac{d}{d x} (\frac{1}{2} ln (x^{2}))

\int \frac{1}{sin ( x ) - cos ( x )} d x

f (x) = 2 x (x^{2} - 4 x + 5)^{6}, at x = 2

\frac{d}{d X} (X^{2})

What is the integral of x/(4+2x^2) ?
The integral of x/(4+2x^2) is 1/4 ln|4+2x^2|+C