What is the tangent of f(x)=2x(x^2-4x+5)^6,\at x=2 ?

The tangent of f(x)=2x(x^2-4x+5)^6,\at x=2 is y=2x

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tangent of f(x)=2x(x^2-4x+5)^6,\at x=2

tangent of

f (x) = 2 x (x^{2} - 4 x + 5)^{6}, at x = 2

y = 2 x

Solution steps

Find the tangent point:

(2, 4)

Find the slope of

f (x) = 2 x (x^{2} - 4 x + 5)^{6} : \frac{df ( x )}{d x} = 2 ((x^{2} - 4 x + 5)^{6} + 6 x (x^{2} - 4 x + 5)^{5} (2 x - 4))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(2, 4) : y = 2 x

y = 2 x

\frac{d}{d X} (X^{2})

\int_{1}^{3} x^{4} (ln (x))^{2} d x

8 e^{- 2 x}

f (x) = x - 2 sin (x)

\int x^{2} + 6 x + 45 d x

What is the tangent of f(x)=2x(x^2-4x+5)^6,\at x=2 ?
The tangent of f(x)=2x(x^2-4x+5)^6,\at x=2 is y=2x