What is the derivative of (x^9-1)^3 ?

The derivative of (x^9-1)^3 is 27x^8(x^9-1)^2

What is the first derivative of (x^9-1)^3 ?

The first derivative of (x^9-1)^3 is 27x^8(x^9-1)^2

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derivative of

(x^{9} - 1)^{3}

27 x^{8} (x^{9} - 1)^{2}

Solution steps

\frac{d}{d x} ((x^{9} - 1)^{3})

Apply the chain rule:

3 (x^{9} - 1)^{2} \frac{d}{d x} (x^{9} - 1)

= 3 (x^{9} - 1)^{2} \frac{d}{d x} (x^{9} - 1)

\frac{d}{d x} (x^{9} - 1) = 9 x^{8}

= 3 (x^{9} - 1)^{2} \cdot 9 x^{8}

Simplify

= 27 x^{8} (x^{9} - 1)^{2}

y = 3 x, y = 2 x - 18, y = 0

\frac{x ^{2} - 6 x + 1}{x ^{2} + 7}

\frac{d}{d x} (\frac{1}{2} e^{\frac{x}{2}})

y^{^{''}} + 4 y^{^{'}} = 5

\int \frac{4}{x} + csc (x) cot (x) d x

What is the derivative of (x^9-1)^3 ?
The derivative of (x^9-1)^3 is 27x^8(x^9-1)^2
What is the first derivative of (x^9-1)^3 ?
The first derivative of (x^9-1)^3 is 27x^8(x^9-1)^2