en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4y^'=5

Solution

y^{^{''}} + 4 y^{^{'}} = 5

Solution

y = c_{1} + c_{2} e^{- 4 t} + \frac{5 t}{4}

Solution steps

y^{''} (t) + 4 y^{'} (t) = 5

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 t} + \frac{5 t}{4}

y = c_{1} + c_{2} e^{- 4 t} + \frac{5 t}{4}

Graph

Popular Examples

integral of 4/x+csc(x)cot(x)

\int \frac{4}{x} + csc (x) cot (x) d x

derivative of (4x/(1+x^2))

\frac{d}{d x} (\frac{4 x}{1 + x ^{2}})

(dy)/(dx)= y/(x^2),y(1)=1

\frac{d y}{d x} = \frac{y}{x ^{2}}, y (1) = 1

limit as x approaches 1+of 4/(x^{(1-x))}

x \to 1 + lim (\frac{4}{x ^{(1 - x)}})

derivative of sec^2(x-1)

\frac{d}{d x} (sec^{2} (x) - 1)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4y^'=5 ?
The solution for y^{''}+4y^'=5 is y=c_{1}+c_{2}e^{-4t}+(5t)/4