What is the derivative of x^3+1/x ?

The derivative of x^3+1/x is 3x^2-1/(x^2)

What is the first derivative of x^3+1/x ?

The first derivative of x^3+1/x is 3x^2-1/(x^2)

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\frac{d}{d x} (x^{3} + \frac{1}{x})

3 x^{2} - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{3} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 3 x^{2} - \frac{1}{x ^{2}}

\int \frac{1}{( 2 + x )} d x

\int \frac{sin ( 2 x )}{22 + cos ^{2} ( x )} d x

\frac{d}{d x} (e^{x} \cdot sin (y))

\frac{x}{( 1 + x ^{2} ) ^{2}}

f (x) = 2 x e^{x^{2}}

What is the derivative of x^3+1/x ?
The derivative of x^3+1/x is 3x^2-1/(x^2)
What is the first derivative of x^3+1/x ?
The first derivative of x^3+1/x is 3x^2-1/(x^2)