What is the integral of 1/((2+x)) ?

The integral of 1/((2+x)) is ln|2+x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((2+x))

\int \frac{1}{( 2 + x )} d x

ln ∣ 2 + x ∣ + C

Solution steps

\int \frac{1}{2 + x} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 2 + x

= ln ∣ 2 + x ∣

Add a constant to the solution

= ln ∣ 2 + x ∣ + C

\int \frac{sin ( 2 x )}{22 + cos ^{2} ( x )} d x

\frac{d}{d x} (e^{x} \cdot sin (y))

\frac{x}{( 1 + x ^{2} ) ^{2}}

f (x) = 2 x e^{x^{2}}

n = 0 \sum \infty (1 - 1 0^{42})^{n}