What is the d/(dy)(\sqrt[3]{y}) ?

The d/(dy)(\sqrt[3]{y}) is 1/(3y^{2/3)}

What is the first d/(dy)(\sqrt[3]{y}) ?

The first d/(dy)(\sqrt[3]{y}) is 1/(3y^{2/3)}

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\frac{d}{d y} (3 y)

\frac{1}{3 y ^{\frac{2}{3}}}

Solution steps

\frac{d}{d y} (3 y)

Apply radical rule:

n a = a^{\frac{1}{n}}

= \frac{d}{d y} (y^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} y^{\frac{1}{3} - 1}

Simplify

\frac{1}{3} y^{\frac{1}{3} - 1} : \frac{1}{3 y ^{\frac{2}{3}}}

= \frac{1}{3 y ^{\frac{2}{3}}}

\int \frac{12 y ^{2}}{4 y ^{3} + 1} d y

\frac{\partial}{\partial x} (sin (8 x - 3 y))

\int \frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )}

n = 0 \sum \infty e^{- \frac{3}{n ^{2}}}

n = 0 \sum \infty (1 + \frac{k}{n})^{n}

What is the d/(dy)(\sqrt[3]{y}) ?
The d/(dy)(\sqrt[3]{y}) is 1/(3y^{2/3)}
What is the first d/(dy)(\sqrt[3]{y}) ?
The first d/(dy)(\sqrt[3]{y}) is 1/(3y^{2/3)}