What is the sum from n=0 to infinity of e^{-3/(n^2)} ?

The sum from n=0 to infinity of e^{-3/(n^2)} is diverges

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sum from n=0 to infinity of e^{-3/(n^2)}

n = 0 \sum \infty e^{- \frac{3}{n ^{2}}}

diverges

Solution steps

n = 1 \sum \infty e^{- \frac{3}{n ^{2}}}

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty (1 + \frac{k}{n})^{n}

\int_{0.5}^{1} \frac{3}{8} (2 - x)^{2} d x

\int_{4}^{5} (t t - 4) d t

\int \frac{1}{ln ( t )} d t

\int 15 + 0.55 x d x

What is the sum from n=0 to infinity of e^{-3/(n^2)} ?
The sum from n=0 to infinity of e^{-3/(n^2)} is diverges