What is the integral of 1/(ln(t)) ?

The integral of 1/(ln(t)) is \Ei(ln(t))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(ln(t))

\int \frac{1}{ln ( t )} d t

Ei (ln (t)) + C

Solution steps

\int \frac{1}{ln ( t )} d t

Apply u-substitution

: \int \frac{e ^{u}}{u} d u

= \int \frac{e ^{u}}{u} d u

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= Ei (u)

Substitute back

u = ln (t)

= Ei (ln (t))

Add a constant to the solution

= Ei (ln (t)) + C

\int 15 + 0.55 x d x

\int x^{- \frac{5}{2}} d x

\frac{2 - 3 s}{s ^{2} - 3}

y = (∣ x - 2 ∣)^{3}, y = 8 - 4 x

x \to 0 lim (\frac{( 2 ^{x} - 1 )}{x})