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Popular >

y^'+1/6 y=40

Solution

y^{^{'}} + \frac{1}{6} y = 40

Solution

y = - e^{\frac{- t - c _{1}}{6}} + 240

Solution steps

y^{'} (t) + \frac{1}{6} y = 40

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{6}} + 240

y = - e^{\frac{- t - c _{1}}{6}} + 240

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+1/6 y=40 ?
The solution for y^'+1/6 y=40 is y=-e^{(-t-c_{1})/6}+240