What is (d^2)/(dx^2)((2x-3)/(3x+1)) ?

The answer to (d^2)/(dx^2)((2x-3)/(3x+1)) is -(66)/((3x+1)^3)

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(d^2)/(dx^2)((2x-3)/(3x+1))

\frac{d ^{2}}{d x ^{2}} (\frac{2 x - 3}{3 x + 1})

- \frac{66}{( 3 x + 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{2 x - 3}{3 x + 1})

\frac{d}{d x} (\frac{2 x - 3}{3 x + 1}) = \frac{11}{( 3 x + 1 ) ^{2}}

= \frac{d}{d x} (\frac{11}{( 3 x + 1 ) ^{2}})

\frac{d}{d x} (\frac{11}{( 3 x + 1 ) ^{2}}) = - \frac{66}{( 3 x + 1 ) ^{3}}

= - \frac{66}{( 3 x + 1 ) ^{3}}

f (x) = x^{4} + 2 \cdot e^{x}, at x = 0

\int 5 sin (\frac{nπ x}{4}) d x

\int 7^{n} ln (7) d n

x \to 3 lim (6 + x)

x \to 0 - lim (e^{- \frac{1}{x}})

What is (d^2)/(dx^2)((2x-3)/(3x+1)) ?
The answer to (d^2)/(dx^2)((2x-3)/(3x+1)) is -(66)/((3x+1)^3)