What is the tangent of f(x)=x^4+2*e^x,\at x=0 ?

The tangent of f(x)=x^4+2*e^x,\at x=0 is y=2x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^4+2*e^x,\at x=0

tangent of

f (x) = x^{4} + 2 \cdot e^{x}, at x = 0

y = 2 x + 2

Solution steps

Find the tangent point:

(0, 2)

Find the slope of

f (x) = x^{4} + 2 e^{x} : \frac{df ( x )}{d x} = 4 x^{3} + 2 e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(0, 2) : y = 2 x + 2

y = 2 x + 2

\int 5 sin (\frac{nπ x}{4}) d x

\int 7^{n} ln (7) d n

x \to 3 lim (6 + x)

x \to 0 - lim (e^{- \frac{1}{x}})

n = 0 \sum \infty sin^{2} (n)

What is the tangent of f(x)=x^4+2*e^x,\at x=0 ?
The tangent of f(x)=x^4+2*e^x,\at x=0 is y=2x+2