What is the derivative of |x^4-4x^2| ?

The derivative of |x^4-4x^2| is ((x^4-4x^2)(4x^3-8x))/(|x^4-4x^2|)

What is the first derivative of |x^4-4x^2| ?

The first derivative of |x^4-4x^2| is ((x^4-4x^2)(4x^3-8x))/(|x^4-4x^2|)

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\frac{d}{d x} (x^{4} - 4 x^{2})

\frac{( x ^{4} - 4 x ^{2} ) ( 4 x ^{3} - 8 x )}{∣ x ^{4} - 4 x ^{2} ∣}

Solution steps

\frac{d}{d x} (x^{4} - 4 x^{2})

Apply the chain rule:

\frac{x ^{4} - 4 x ^{2}}{∣ ( x ^{4} - 4 x ^{2} ) ∣} \frac{d}{d x} (x^{4} - 4 x^{2})

= \frac{x ^{4} - 4 x ^{2}}{∣ ( x ^{4} - 4 x ^{2} ) ∣} \frac{d}{d x} (x^{4} - 4 x^{2})

\frac{d}{d x} (x^{4} - 4 x^{2}) = 4 x^{3} - 8 x

= \frac{x ^{4} - 4 x ^{2}}{∣ ( x ^{4} - 4 x ^{2} ) ∣} (4 x^{3} - 8 x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{4} - 4 x ^{2} ) ( 4 x ^{3} - 8 x )}{∣ x ^{4} - 4 x ^{2} ∣}

\int cos^{2} (2 θ) d θ

\int \frac{3 x ^{2}}{( x ^{3} + 3 ) ^{2}} d x

\frac{\partial}{\partial x} (2 x^{2} + 9 y^{2})

\int 2 e^{3 x + e^{3 x}} d x

\frac{d}{d t} (2 e^{t} cos (t))

What is the derivative of |x^4-4x^2| ?
The derivative of |x^4-4x^2| is ((x^4-4x^2)(4x^3-8x))/(|x^4-4x^2|)
What is the first derivative of |x^4-4x^2| ?
The first derivative of |x^4-4x^2| is ((x^4-4x^2)(4x^3-8x))/(|x^4-4x^2|)