What is the integral of 9sin(t) ?

The integral of 9sin(t) is -9cos(t)+C

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integral of 9sin(t)

\int 9 sin (t) d t

- 9 cos (t) + C

Solution steps

\int 9 sin (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= 9 (- cos (t))

Simplify

= - 9 cos (t)

Add a constant to the solution

= - 9 cos (t) + C

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