What is the derivative of 1/(sin(2x)) ?

The derivative of 1/(sin(2x)) is -cot(2x)csc(2x)*2

What is the first derivative of 1/(sin(2x)) ?

The first derivative of 1/(sin(2x)) is -cot(2x)csc(2x)*2

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\frac{d}{d x} (\frac{1}{sin ( 2 x )})

- cot (2 x) csc (2 x) \cdot 2

Solution steps

\frac{d}{d x} (\frac{1}{sin ( 2 x )})

Simplify

\frac{1}{sin ( 2 x )} : csc (2 x)

= \frac{d}{d x} (csc (2 x))

Apply the chain rule:

- cot (2 x) csc (2 x) \frac{d}{d x} (2 x)

= - cot (2 x) csc (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - cot (2 x) csc (2 x) \cdot 2

\frac{e ^{- s} - e ^{- 2 s}}{s ( s + 2 ) ( s + 1 )}

\int_{1}^{2} x 8^{x^{2}} d x

y^{^{'}} = \frac{y ( x - y )}{x ^{2}}

\frac{d y}{d x} = 2 + 3 y

x \to 0 lim (ln (x^{2}) (- 2))

What is the derivative of 1/(sin(2x)) ?
The derivative of 1/(sin(2x)) is -cot(2x)csc(2x)*2
What is the first derivative of 1/(sin(2x)) ?
The first derivative of 1/(sin(2x)) is -cot(2x)csc(2x)*2