What is taylor e^x1 ?

The answer to taylor e^x1 is 1+x+1/2 x^2+1/6 x^3+1/24 x^4+\ldots

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taylor e^x1

taylor

e^{x} 1

1 + x + \frac{1}{2} x^{2} + \frac{1}{6} x^{3} + \frac{1}{24} x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( e ^{x} \cdot 1 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{x} \cdot 1 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{x} \cdot 1 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{1}{1 !} x + \frac{1}{2 !} x^{2} + \frac{1}{3 !} x^{3} + \frac{1}{4 !} x^{4} + \dots

Refine

= 1 + x + \frac{1}{2} x^{2} + \frac{1}{6} x^{3} + \frac{1}{24} x^{4} + \dots

n = 0 \sum \infty \frac{1}{9}

\int \frac{5 x}{x - 1} d x

(0, 0), (6, 4)

\int_{0}^{\frac{π}{2}} x^{2} sin (2 x) d x

x \to 0 lim (\frac{( sin ( 4 x ) )}{2 x})

What is taylor e^x1 ?
The answer to taylor e^x1 is 1+x+1/2 x^2+1/6 x^3+1/24 x^4+\ldots