What is the solution for f^'(x)=tan(x)+cot(x) ?

The solution for f^'(x)=tan(x)+cot(x) is f(x)=-ln(cos(x))+ln(sin(x))+c_{1}

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f^'(x)=tan(x)+cot(x)

f^{^{'}} (x) = tan (x) + cot (x)

f (x) = - ln (cos (x)) + ln (sin (x)) + c_{1}

Solution steps

f^{'} (x) = tan (x) + cot (x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int tan (x) + cot (x) d x

\int tan (x) + cot (x) d x = - ln (cos (x)) + ln (sin (x)) + c_{1}

f (x) = - ln (cos (x)) + ln (sin (x)) + c_{1}

\int sin (a t) d t

\frac{d y}{d x} + y cos (x) = 5 cos (x)

x \to 2 lim (e^{\frac{1}{x}})

1 - e^{- x}

\int 1 - sin (x) d x

What is the solution for f^'(x)=tan(x)+cot(x) ?
The solution for f^'(x)=tan(x)+cot(x) is f(x)=-ln(cos(x))+ln(sin(x))+c_{1}