What is the derivative of in(3x+1(x+2)2) ?

The derivative of in(3x+1(x+2)2) is i(14n+12nx)

What is the first derivative of in(3x+1(x+2)2) ?

The first derivative of in(3x+1(x+2)2) is i(14n+12nx)

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\frac{d}{d x} (in (3 x + 1) (x + 2) 2)

i (14 n + 12 n x)

Solution steps

\frac{d}{d x} (in (3 x + 1) (x + 2) \cdot 2)

Simplify

in (3 x + 1) (x + 2) \cdot 2 : i (4 n + 14 n x + 6 n x^{2})

= \frac{d}{d x} (i (4 n + 14 n x + 6 n x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= i \frac{d}{d x} (4 n + 14 n x + 6 n x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= i (\frac{d}{d x} (4 n) + \frac{d}{d x} (14 n x) + \frac{d}{d x} (6 n x^{2}))

\frac{d}{d x} (4 n) = 0

\frac{d}{d x} (14 n x) = 14 n

\frac{d}{d x} (6 n x^{2}) = 12 n x

= i (0 + 14 n + 12 n x)

Simplify

i (0 + 14 n + 12 n x) : i (14 n + 12 n x)

= i (14 n + 12 n x)

a x^{n} + b x^{n - 1}

\int 2 x^{3} - 6 x^{2} d x

\frac{d y}{d x} + y = \frac{1 - e ^{- 2 x}}{e ^{x} + e ^{- x}}

cos (3 cos (2 u))

\frac{d}{d x} (x^{- 4} + cos (x))

What is the derivative of in(3x+1(x+2)2) ?
The derivative of in(3x+1(x+2)2) is i(14n+12nx)
What is the first derivative of in(3x+1(x+2)2) ?
The first derivative of in(3x+1(x+2)2) is i(14n+12nx)