What is the derivative of (x^2-x^2-2(x^2-x)) ?

The derivative of (x^2-x^2-2(x^2-x)) is 4x^3-6x^2-2x+2

What is the first derivative of (x^2-x^2-2(x^2-x)) ?

The first derivative of (x^2-x^2-2(x^2-x)) is 4x^3-6x^2-2x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((x^{2} - x)^{2} - 2 (x^{2} - x))

4 x^{3} - 6 x^{2} - 2 x + 2

Solution steps

\frac{d}{d x} ((x^{2} - x)^{2} - 2 (x^{2} - x))

Simplify

(x^{2} - x)^{2} - 2 (x^{2} - x) : x^{4} - 2 x^{3} - x^{2} + 2 x

= \frac{d}{d x} (x^{4} - 2 x^{3} - x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

= 4 x^{3} - 6 x^{2} - 2 x + 2

\frac{d}{d x} (x x + 2)

f (x) = x^{4} - 8 x^{3}

\frac{d}{d x} (cos (- 5 ln (- 3 x - 1)))

\int \frac{( 1 + y )}{y} d y

f (x) = (x + 1)

What is the derivative of (x^2-x^2-2(x^2-x)) ?
The derivative of (x^2-x^2-2(x^2-x)) is 4x^3-6x^2-2x+2
What is the first derivative of (x^2-x^2-2(x^2-x)) ?
The first derivative of (x^2-x^2-2(x^2-x)) is 4x^3-6x^2-2x+2