What is the derivative of f(x)=(x+1) ?

The derivative of f(x)=(x+1) is 1

What is the first derivative of f(x)=(x+1) ?

The first derivative of f(x)=(x+1) is 1

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derivative of

f (x) = (x + 1)

1

Solution steps

\frac{d}{d x} ((x + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 + 0

Simplify

= 1

\int_{0}^{l n (2)} e^{x} - 1 d x

y = (6 x + 5)^{2}

\frac{\partial}{\partial x} (\frac{x}{( x ^{2} + y ^{2} + z ^{2} )})

y^{^{''}} - x y^{^{'}} + y = 0

\int (x^{\frac{1}{3}}) d x

What is the derivative of f(x)=(x+1) ?
The derivative of f(x)=(x+1) is 1
What is the first derivative of f(x)=(x+1) ?
The first derivative of f(x)=(x+1) is 1