What is the derivative of 4x^2+25 ?

The derivative of 4x^2+25 is 8x

What is the first derivative of 4x^2+25 ?

The first derivative of 4x^2+25 is 8x

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derivative of

4 x^{2} + 25

8 x

Solution steps

\frac{d}{d x} (4 x^{2} + 25)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (25)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (25) = 0

= 8 x + 0

Simplify

= 8 x

\frac{d x}{d t} = - 0.1 (x - 100 + 40 e^{- 0.1 t})

x \to 2 - lim (ln ∣ x - 2 ∣)

\int \frac{1}{x ^{2} - y ^{2}} d y

f (x) = \frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}

x \to 0 - lim (e^{\frac{5}{x}})