What is the solution for (dy)/(e^{-2y)}=8x^3dx ?

The solution for (dy)/(e^{-2y)}=8x^3dx is y=(ln(4x^4+c_{1}))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(e^{-2y)}=8x^3dx

\frac{d y}{e ^{- 2 y}} = 8 x^{3} d x

y = \frac{ln ( 4 x ^{4} + c _{1} )}{2}

Solution steps

\frac{d y}{e ^{- 2 y}} = 8 x^{3} d x

Solve separable ODE:

y = \frac{ln ( 4 x ^{4} + c _{1} )}{2}

y = \frac{ln ( 4 x ^{4} + c _{1} )}{2}

\frac{\partial}{\partial y} (9 x^{\frac{y}{z}})

\frac{d}{d x} (\frac{sin ( 3 x )}{cos ( 2 x )})

arcsin (\frac{x}{9})

f (x) = \frac{e ^{x}}{x}, e, at x = 1

\int (9 x - 6)^{2} d x

What is the solution for (dy)/(e^{-2y)}=8x^3dx ?
The solution for (dy)/(e^{-2y)}=8x^3dx is y=(ln(4x^4+c_{1}))/2