What is the derivative of (sin(3x)/(cos(2x))) ?

The derivative of (sin(3x)/(cos(2x))) is cos(3x)*3sec(2x)+sec(2x)tan(2x)*2sin(3x)

What is the first derivative of (sin(3x)/(cos(2x))) ?

The first derivative of (sin(3x)/(cos(2x))) is cos(3x)*3sec(2x)+sec(2x)tan(2x)*2sin(3x)

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\frac{d}{d x} (\frac{sin ( 3 x )}{cos ( 2 x )})

cos (3 x) \cdot 3 sec (2 x) + sec (2 x) tan (2 x) \cdot 2 sin (3 x)

Solution steps

\frac{d}{d x} (\frac{sin ( 3 x )}{cos ( 2 x )})

Simplify

\frac{sin ( 3 x )}{cos ( 2 x )} : sin (3 x) sec (2 x)

= \frac{d}{d x} (sin (3 x) sec (2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (3 x), g = sec (2 x)

= \frac{d}{d x} (sin (3 x)) sec (2 x) + \frac{d}{d x} (sec (2 x)) sin (3 x)

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

\frac{d}{d x} (sec (2 x)) = sec (2 x) tan (2 x) \cdot 2

= cos (3 x) \cdot 3 sec (2 x) + sec (2 x) tan (2 x) \cdot 2 sin (3 x)

arcsin (\frac{x}{9})

f (x) = \frac{e ^{x}}{x}, e, at x = 1

\int (9 x - 6)^{2} d x

- x e^{x}

y^{2} = x + 4, y^{2} = 2 - x

What is the derivative of (sin(3x)/(cos(2x))) ?
The derivative of (sin(3x)/(cos(2x))) is cos(3x)*3sec(2x)+sec(2x)tan(2x)*2sin(3x)
What is the first derivative of (sin(3x)/(cos(2x))) ?
The first derivative of (sin(3x)/(cos(2x))) is cos(3x)*3sec(2x)+sec(2x)tan(2x)*2sin(3x)