What is the tangent of x^4-3x^2+9 ?

The tangent of x^4-3x^2+9 is y=(4a_{0}^3-6a_{0})x-3a_{0}^4+3a_{0}^2+9

Popular >

tangent of x^4-3x^2+9

tangent of

x^{4} - 3 x^{2} + 9

y = (4 a_{0}^{3} - 6 a_{0}) x - 3 a_{0}^{4} + 3 a_{0}^{2} + 9

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{4} - 3 a_{0}^{2} + 9)

Find the slope of

y = x^{4} - 3 x^{2} + 9 : \frac{d y}{d x} = 4 x^{3} - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0}^{3} - 6 a_{0}

Find the line with slope m=

4 a_{0}^{3} - 6 a_{0}

and passing through

(a_{0}, a_{0}^{4} - 3 a_{0}^{2} + 9) : y = (4 a_{0}^{3} - 6 a_{0}) x - 3 a_{0}^{4} + 3 a_{0}^{2} + 9

y = (4 a_{0}^{3} - 6 a_{0}) x - 3 a_{0}^{4} + 3 a_{0}^{2} + 9

\int x^{2} e^{- \frac{x}{2}} d x

\int (x + 6) (x - 5) d x

\frac{d}{d x} (sin (tan (cos (2 π x^{4}))))

x \to - \infty lim (x ln (x))

\frac{d}{d x} (\frac{x - 1}{x + 1})

What is the tangent of x^4-3x^2+9 ?
The tangent of x^4-3x^2+9 is y=(4a_{0}^3-6a_{0})x-3a_{0}^4+3a_{0}^2+9