What is the integral of x^2e^{-x/2} ?

The integral of x^2e^{-x/2} is -2e^{-x/2}x^2+4(-2e^{-x/2}x-4e^{-x/2})+C

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integral of x^2e^{-x/2}

\int x^{2} e^{- \frac{x}{2}} d x

- 2 e^{- \frac{x}{2}} x^{2} + 4 (- 2 e^{- \frac{x}{2}} x - 4 e^{- \frac{x}{2}}) + C

Solution steps

\int x^{2} e^{- \frac{x}{2}} d x

Apply Integration By Parts

: - 2 e^{- \frac{x}{2}} x^{2} - \int - 4 e^{- \frac{x}{2}} x d x

= - 2 e^{- \frac{x}{2}} x^{2} - \int - 4 e^{- \frac{x}{2}} x d x

\int - 4 e^{- \frac{x}{2}} x d x = - 4 (- 2 e^{- \frac{x}{2}} x - 4 e^{- \frac{x}{2}})

= - 2 e^{- \frac{x}{2}} x^{2} - (- 4 (- 2 e^{- \frac{x}{2}} x - 4 e^{- \frac{x}{2}}))

Simplify

= - 2 e^{- \frac{x}{2}} x^{2} + 4 (- 2 e^{- \frac{x}{2}} x - 4 e^{- \frac{x}{2}})

Add a constant to the solution

= - 2 e^{- \frac{x}{2}} x^{2} + 4 (- 2 e^{- \frac{x}{2}} x - 4 e^{- \frac{x}{2}}) + C

\int (x + 6) (x - 5) d x

\frac{d}{d x} (sin (tan (cos (2 π x^{4}))))

x \to - \infty lim (x ln (x))

\frac{d}{d x} (\frac{x - 1}{x + 1})

\frac{d}{d x} (x^{2} + x^{2} ln (x))

What is the integral of x^2e^{-x/2} ?
The integral of x^2e^{-x/2} is -2e^{-x/2}x^2+4(-2e^{-x/2}x-4e^{-x/2})+C