What is the derivative of sqrt(16x) ?

The derivative of sqrt(16x) is 2/(sqrt(x))

What is the first derivative of sqrt(16x) ?

The first derivative of sqrt(16x) is 2/(sqrt(x))

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\frac{d}{d x} (16 x)

\frac{2}{x}

Solution steps

\frac{d}{d x} (16 x)

Apply the chain rule:

\frac{1}{2 16 x} \frac{d}{d x} (16 x)

= \frac{1}{2 16 x} \frac{d}{d x} (16 x)

\frac{d}{d x} (16 x) = 16

= \frac{1}{2 16 x} \cdot 16

Simplify

\frac{1}{2 16 x} \cdot 16 : \frac{2}{x}

= \frac{2}{x}

\frac{d}{d y} (y ln (y) - e^{- x y})

\int \frac{2 sin ( \frac{1}{5 x} )}{5 x ^{2}} d x

y = \frac{64}{16 + x ^{2}}, y = 1

\int 2 sec (4 x) d x

\frac{1}{s + 42} - \frac{1}{( s + 3 ) ^{4}}

What is the derivative of sqrt(16x) ?
The derivative of sqrt(16x) is 2/(sqrt(x))
What is the first derivative of sqrt(16x) ?
The first derivative of sqrt(16x) is 2/(sqrt(x))