What is area y=(64)/(16+x^2),y=1 ?

The answer to area y=(64)/(16+x^2),y=1 is (32pi)/3-8sqrt(3)

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area y=(64)/(16+x^2),y=1

area

y = \frac{64}{16 + x ^{2}}, y = 1

\frac{32 π}{3} - 83

Decimal

19.65391 \dots

Solution steps

Apply the area formula:

\int_{- 43}^{43} \frac{64}{16 + x ^{2}} - 1 d x

Solve

\int_{- 43}^{43} \frac{64}{16 + x ^{2}} - 1 d x : \frac{32 π}{3} - 83

The area is:

= \frac{32 π}{3} - 83

\int 2 sec (4 x) d x

\frac{1}{s + 42} - \frac{1}{( s + 3 ) ^{4}}

\int - π cos (1 π) t d t

\frac{\partial}{\partial x} (- 2 e^{3 x})

\frac{d}{d x} (cos (a x))

What is area y=(64)/(16+x^2),y=1 ?
The answer to area y=(64)/(16+x^2),y=1 is (32pi)/3-8sqrt(3)