What is the integral of-picos(1pi)t ?

The integral of-picos(1pi)t is (pit^2)/2+C

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integral of-picos(1pi)t

\int - π cos (1 π) t d t

\frac{π t ^{2}}{2} + C

Solution steps

\int - π cos (1 π) t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - π cos (1 π) \cdot \int t d t

- π cos (1 π) = π

= π \cdot \int t d t

Apply the Power Rule

: \frac{t ^{2}}{2}

= π \frac{t ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π t ^{2}}{2}

Add a constant to the solution

= \frac{π t ^{2}}{2} + C

\frac{\partial}{\partial x} (- 2 e^{3 x})

\frac{d}{d x} (cos (a x))

11 - x^{2}

\int_{0}^{2} \frac{1}{1 - x ^{2}} d x

\frac{d}{d x} (ln (\frac{1 + cos ( x )}{1 - cos ( x )}))

What is the integral of-picos(1pi)t ?
The integral of-picos(1pi)t is (pit^2)/2+C