What is the tangent of 11-x^2 ?

The tangent of 11-x^2 is y=-2a_{0}x+11+a_{0}^2

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tangent of 11-x^2

tangent of

11 - x^{2}

y = - 2 a_{0} x + 11 + a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 11 - a_{0}^{2})

Find the slope of

y = 11 - x^{2} : \frac{d y}{d x} = - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2 a_{0}

Find the line with slope m=

- 2 a_{0}

and passing through

(a_{0}, 11 - a_{0}^{2}) : y = - 2 a_{0} x + 11 + a_{0}^{2}

y = - 2 a_{0} x + 11 + a_{0}^{2}

\int_{0}^{2} \frac{1}{1 - x ^{2}} d x

\frac{d}{d x} (ln (\frac{1 + cos ( x )}{1 - cos ( x )}))

\int \frac{1}{( x ^{2} - 4 x - 5 )} d x

x^{4} + 2 x, 1

(12 x + x^{2} + 0.05 x^{3})^{^{'}}