What is the solution for (dy)/(dx)=e^{y/x}+y/x ?

The solution for (dy)/(dx)=e^{y/x}+y/x is y=-xln(-ln(x)-c_{1})

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(dy)/(dx)=e^{y/x}+y/x

\frac{d y}{d x} = e^{\frac{y}{x}} + \frac{y}{x}

y = - x ln (- ln (x) - c_{1})

Solution steps

\frac{d y}{d x} = e^{\frac{y}{x}} + \frac{y}{x}

Solve using substitution:

y = - x ln (- ln (x) - c_{1})

y = - x ln (- ln (x) - c_{1})

\int x^{3} (9 + x^{4})^{6} d x

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n = 1 \sum \infty \frac{( n + 2 )}{2 ^{n}}

\frac{\partial}{\partial x} (4 (\frac{y}{x})^{\frac{1}{2}})

f (x) = 2 x^{2} + 2, [- 2, 3]

What is the solution for (dy)/(dx)=e^{y/x}+y/x ?
The solution for (dy)/(dx)=e^{y/x}+y/x is y=-xln(-ln(x)-c_{1})