What is the sum from n=1 to infinity of (n-7)/(n+7) ?

The sum from n=1 to infinity of (n-7)/(n+7) is diverges

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sum from n=1 to infinity of (n-7)/(n+7)

n = 1 \sum \infty \frac{n - 7}{n + 7}

diverges

Solution steps

n = 1 \sum \infty \frac{n - 7}{n + 7}

Apply Series Divergence Test:

diverges

= diverges

f (x) = sec^{5} (x)

\frac{d}{d x} (\frac{128000}{x} + x^{2})

\frac{\partial}{\partial x} (3 x^{2} + 4 x y + 2 y^{2})

\frac{\partial}{\partial x} (\frac{9 x y}{x - y})

4 cos (x), at x = - \frac{π}{3}

What is the sum from n=1 to infinity of (n-7)/(n+7) ?
The sum from n=1 to infinity of (n-7)/(n+7) is diverges