What is the tangent of 4cos(x),\at x=-pi/3 ?

The tangent of 4cos(x),\at x=-pi/3 is y=2sqrt(3)x+2+(2pi)/(sqrt(3))

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tangent of 4cos(x),\at x=-pi/3

tangent of

4 cos (x), at x = - \frac{π}{3}

y = 23 x + 2 + \frac{2 π}{3}

Solution steps

Find the tangent point:

(- \frac{π}{3}, 2)

Find the slope of

y = 4 cos (x) : \frac{d y}{d x} = - 4 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 23

Find the line with slope m=

23

and passing through

(- \frac{π}{3}, 2) : y = 23 x + 2 + \frac{2 π}{3}

y = 23 x + 2 + \frac{2 π}{3}

\int \frac{y}{2 + y ^{2}} d y

(x^{2} - 12), (x - 6)

\frac{d}{d x} (x^{3} - x - 1)

(x - 2)^{2} - sin (3 x)

\int \frac{3 - 2 x}{5 x + 7} d x

What is the tangent of 4cos(x),\at x=-pi/3 ?
The tangent of 4cos(x),\at x=-pi/3 is y=2sqrt(3)x+2+(2pi)/(sqrt(3))