What is the derivative of x^3-x-1 ?

The derivative of x^3-x-1 is 3x^2-1

What is the first derivative of x^3-x-1 ?

The first derivative of x^3-x-1 is 3x^2-1

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\frac{d}{d x} (x^{3} - x - 1)

3 x^{2} - 1

Solution steps

\frac{d}{d x} (x^{3} - x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 3 x^{2} - 1 - 0

Simplify

= 3 x^{2} - 1

(x - 2)^{2} - sin (3 x)

\int \frac{3 - 2 x}{5 x + 7} d x

\int_{1}^{2} 9 r^{4} ln (r) d r

y^{^{'}} + 2 t y = t

\frac{d y}{d x} = \frac{2 x}{3 y}

What is the derivative of x^3-x-1 ?
The derivative of x^3-x-1 is 3x^2-1
What is the first derivative of x^3-x-1 ?
The first derivative of x^3-x-1 is 3x^2-1