What is the solution for (dy)/(dx)=(2x)/(3y) ?

The solution for (dy)/(dx)=(2x)/(3y) is y=sqrt((2x^2)/3+c_{1)},y=-sqrt((2x^2)/3+c_{1)}

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(dy)/(dx)=(2x)/(3y)

\frac{d y}{d x} = \frac{2 x}{3 y}

y = \frac{2 x ^{2}}{3} + c_{1}, y = - \frac{2 x ^{2}}{3} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{2 x}{3 y}

Solve separable ODE:

y = \frac{2 x ^{2}}{3} + c_{1}, y = - \frac{2 x ^{2}}{3} + c_{1}

y = \frac{2 x ^{2}}{3} + c_{1}, y = - \frac{2 x ^{2}}{3} + c_{1}

\frac{cos ( x )}{x ^{8}}

y = 8 x sin (x)

\int_{0}^{0.5} 2 x d x

- 0.04 x^{2} - 0.8 x + 70

\int 1 + 4 t^{2} d t

What is the solution for (dy)/(dx)=(2x)/(3y) ?
The solution for (dy)/(dx)=(2x)/(3y) is y=sqrt((2x^2)/3+c_{1)},y=-sqrt((2x^2)/3+c_{1)}