What is the tangent of-0.04x^2-0.8x+70 ?

The tangent of-0.04x^2-0.8x+70 is y=(-0.08a_{0}-0.8)x+0.04a_{0}^2+70

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tangent of-0.04x^2-0.8x+70

tangent of

- 0.04 x^{2} - 0.8 x + 70

y = (- 0.08 a_{0} - 0.8) x + 0.04 a_{0}^{2} + 70

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 0.04 a_{0}^{2} - 0.8 a_{0} + 70)

Find the slope of

y = - 0.04 x^{2} - 0.8 x + 70 : \frac{d y}{d x} = - 0.08 x - 0.8

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 0.08 a_{0} - 0.8

Find the line with slope m=

- 0.08 a_{0} - 0.8

and passing through

(a_{0}, - 0.04 a_{0}^{2} - 0.8 a_{0} + 70) : y = (- 0.08 a_{0} - 0.8) x + 0.04 a_{0}^{2} + 70

y = (- 0.08 a_{0} - 0.8) x + 0.04 a_{0}^{2} + 70

\int 1 + 4 t^{2} d t

x \to 2 + lim (\frac{- 5}{x - 2})

x \to - 4 + lim (\frac{3}{x ^{2} - 16})

f (x) = x^{3} - 6 x + 9

\int (\frac{1}{2 x}) d x

What is the tangent of-0.04x^2-0.8x+70 ?
The tangent of-0.04x^2-0.8x+70 is y=(-0.08a_{0}-0.8)x+0.04a_{0}^2+70