What is the integral of x/(x-3) ?

The integral of x/(x-3) is x-3+3ln|x-3|+C

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integral of x/(x-3)

\int \frac{x}{x - 3} d x

x - 3 + 3 ln ∣ x - 3 ∣ + C

Solution steps

\int \frac{x}{x - 3} d x

Apply u-substitution

: \int \frac{u + 3}{u} d u

= \int \frac{u + 3}{u} d u

Expand

\frac{u + 3}{u} : 1 + \frac{3}{u}

= \int 1 + \frac{3}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u + \int \frac{3}{u} d u

\int 1 d u = u

\int \frac{3}{u} d u = 3 ln ∣ u ∣

= u + 3 ln ∣ u ∣

Substitute back

u = x - 3

= x - 3 + 3 ln ∣ x - 3 ∣

Add a constant to the solution

= x - 3 + 3 ln ∣ x - 3 ∣ + C

\frac{d}{d x} (- x^{3} + x)

4 cos (7 x), 4 - 4 cos (7 x), 0, \frac{π}{7}

\frac{( s + 1 )}{s ^{2} + 1}

\frac{9}{x}

x \to 0 - lim (3^{\frac{1}{x}})